Which of the following are solutions to the equation below x^2+8x+16=2

Answer:[tex]x_{1} =-4+\sqrt{2} \\x_{2} =-4-\sqrt{2} \\[/tex]Step-by-step explanation:Using quadratic formula:[tex]\frac{-b+-\sqrt{b^{2} -4*a*c} }{2*a}[/tex]We will have 2 solutions.x^2+8x+16=2 x^2+8x+14=0a= 1    b=8   c= 14[tex]x_{1}= \frac{-8+\sqrt{8^{2}-4*1*14} }{2*1} \\\\x_{2}= \frac{-8-\sqrt{8^{2}-4*1*14} }{2*1} \\[/tex]We can write:[tex]x_{1}= \frac{-8+\sqrt{{64}-56} }{2} \\\\x_{2}= \frac{-8-\sqrt{{64}-56} }{2} \\[/tex][tex]x_{1}= -4+\frac{\sqrt{{64}-56} }{2} \\\\x_{2}= -4-\frac{\sqrt{{64}-56} }{2} \\[/tex]so, we have:[tex]x_{1}= -4+\frac{\sqrt{{}8} }{2} \\\\x_{2}=-4-\frac{\sqrt{{}8} }{2} \\[/tex]simplifying we have:[tex]x_{1}= -4+\frac{\sqrt{{}2*4} }{2} \\\\x_{2}= -4-\frac{\sqrt{{}2*4} }{2} \\[/tex]Finally:[tex]x_{1}= -4+\sqrt{2} \\\\x_{2}= -4-\sqrt{2} \\[/tex]