MATH SOLVE

4 months ago

Q:
# Rolling a Red and Yellow Dice(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)A red die and a yellow die are rolled. The outcome "3 on the red die and 4 on the yellow die" can be represented by the ordered pair (3,4). What is the probability that the sum of the die is lucky number 7? 1/25/61/91/6

Accepted Solution

A:

Answer:1/6Step-by-step explanation:The total number of possible outcomes are:(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6) = 36The possible outcomes with sum 7 from the sample space are:(1,6)(2,5)(3,4)(4,3)(5,2)(6,1) = 6The probability with the sum 7 is: [tex]\frac{Desired Outcomes}{Possible Outcomes} = \frac{6}{36}[/tex]=> [tex]\frac{1}{6}[/tex]Hence the last option is correct.